Acceleration (with and without friction)

AI Thread Summary
The discussion revolves around calculating the acceleration of a skier on a 25-degree incline, both with and without friction. When friction is negligible, the expected acceleration is 4.41 m/s², while with a friction force of 45N, the acceleration should be 3.4 m/s². The initial calculations provided were incorrect, as the user obtained 1.30 m/s² and 2.05 m/s² respectively. A suggestion was made to isolate acceleration in the formula (a=F/m) to simplify the calculations. Correcting the approach should yield the expected results.
tascja
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Homework Statement


Consider the skier on the slope. She and her equipment have a mass of 60kg. She is on an incline that makes a 25deg incline [she is sliding down the hill].
a. what is her acceleration if friction is negligible?
b. what is her acceleration if friction is known to be 45N?

Homework Equations


Fnet = ma

The Attempt at a Solution


a.
Fnet = ma
588sin25 = 60a
a = 1.30 m/s^2

b.
Fnet = ma
588sin25 - 45 = 60a
a = 2.05 m/s^2

im not sure what I am doing wrong. but the answer book says i should be getting a) 4.41m/s^2 and for b)3.4 m/s^2. If someone could please explain where I am going wrong that would be greatly appreciated :)
 
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You seem to be setting up the problem correctly, but the calculation is off. Try instead to find the answer with acceleration isolated (a=F/m). That might make calculating things simpler.
 
Kindly see the attached pdf. My attempt to solve it, is in it. I'm wondering if my solution is right. My idea is this: At any point of time, the ball may be assumed to be at an incline which is at an angle of θ(kindly see both the pics in the pdf file). The value of θ will continuously change and so will the value of friction. I'm not able to figure out, why my solution is wrong, if it is wrong .
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...

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