Acceleration with limited known variables Question

AI Thread Summary
The discussion revolves around calculating the acceleration of a bush baby during its vertical leap of 2.26 meters, with an acceleration distance of 0.160 meters. The user attempts to apply kinematic equations but struggles with the correct application and units, mistakenly reporting acceleration in m/s instead of m/s². They calculate an initial velocity and derive an acceleration of 128.625 m/s², but this is incorrect according to the expected answer of 138 m/s². The confusion stems from the proper application of the equations and the handling of units throughout the calculations. Clarification on the correct approach and units is needed to resolve the discrepancies in the results.
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Homework Statement



A bush baby, an African primate, is capable of leaping vertically to the remarkable height of 2.26 m. To jump this high, the bush baby accelerates over a distance of 0.160 m, while extending the legs. The acceleration during the jump is approximately constant. What is the acceleration in m/s?

h=2.26m
d=.160m
g=9.8m/s

Homework Equations



d=.5 X a X t
V=a X t
h=V X t-1/2g(t^2)
0=V - g X t


The Attempt at a Solution



I have no idea how to attempt this without another variable given.
 
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bbauer2 said:

Homework Statement



A bush baby, an African primate, is capable of leaping vertically to the remarkable height of 2.26 m. To jump this high, the bush baby accelerates over a distance of 0.160 m, while extending the legs. The acceleration during the jump is approximately constant. What is the acceleration in m/s?

h=2.26m
d=.160m
g=9.8m/s

Homework Equations



d=.5 X a X t
V=a X t
h=V X t-1/2g(t^2)
0=V - g X t


The Attempt at a Solution



I have no idea how to attempt this without another variable given.

Acceleration is in m/s^2, not m/s.

The acceleration happens first, to give a Vo. Then the rest is just governed by the simple/regular gravity kinematic equations. Show your work.
 
Here's what I got, and I submitted it and it's still wrong. Can anyone tell me where I am going wrong?

The square of the max initial velocity Vo² = 2gh where h is 2.16 - .16 = 2.1 m.

Vo² = 41.16 m²/s²

To reach this speed in a jump of y meters, a = Vo²/(2y) = 41.16/(2*.16)

a = 128.625 m/s = 13.125 g's
 
bbauer2 said:
Here's what I got, and I submitted it and it's still wrong. Can anyone tell me where I am going wrong?

The square of the max initial velocity Vo² = 2gh where h is 2.16 - .16 = 2.1 m.

Vo² = 41.16 m²/s²

To reach this speed in a jump of y meters, a = Vo²/(2y) = 41.16/(2*.16)

a = 128.625 m/s = 13.125 g's

The numbers look right to me, except for the units on the final answer (I'll say again, the units of acceleration are m/s^2, not m/s). If you carried the units along in your equations above the answer, you would have gotten the same number and the correct units.

If you submit a = 128.63 m/s^2, is it still wrong?
 
Yeah, it's wrong. All I need is the numbers, the m/s^2 is given. It said the answer is 138! Anyone know how they got that?
 
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