Automotive Air speed in car radiator -- Heat Exchange calculations

AI Thread Summary
The discussion revolves around calculating the heat exchange area of a car radiator using the equation Q = U*A*LMTD. The user is attempting to determine the external convection coefficient, which requires the Reynolds number, dependent on air speed. They express concern that their initial calculation for air speed does not account for the fins, leading to potentially inaccurate results. Other participants suggest that experimental methods to determine the heat transfer coefficient U could be more effective, emphasizing the need for research into existing heat transfer correlations for air flow across finned tubes. The conversation highlights the complexities of accurately modeling forced convection in radiator systems.
r4m0n0
Messages
2
Reaction score
0
Hello, this is my first post. This question is related to my final thesis.

I'm calculating the heat exchange area of a radiator through heat exchange equations:

Q = U*A*LMTD

I have as data Q, and LMTD (this one through trivial calculations)

In order to calculate U, I need the coefficients for external and internal (both tubes and fins) convection.
Internal convection coefficient is quite easy to calculate.
My doubts come when trying to calculate the external convection coefficient. As you may know to calculate the coefficient you need the Reynolds number (amongst other things).
Reynolds depends on the fluid speed (in this case air speed) and in order to calculate it I thought of the following equation:

v=(V_dot_air)/(no.of tubes*area of tubes) --->

The thing is... this calculation doesn't take in account the fins of the radiator, thus not having an accurate value for velocity.
But if I took in account the area of the fins into the equation, the velocity of air would be very VERY slow.

Can anyone suggest a better way to calculate air speed through a car radiator?

Thanks in advance :)
cross_flow_square_fins.png

(Image enclosed: a simplification of a car radiator)
 
Engineering news on Phys.org
It's forced convection not natural convection .

Mass flow and velocity of cooling air is primarily determined by the cooling fan and possibly by forward velocity of vehicle depending on ducting arrangement .
 
If you have data on Q and LMTD, then you have enough to calculate U experimentally. So why are you trying to calculate it from the flows?

Chet
 
@Nidum:

Yes, it is forced convection, I never said otherwise. I'm calculating the air velocity "from scratch" so in order to know how the ducting arrangement and the cooling fan type/size I must calculate before the air velocity.

@Chestermiller:

Calculate U experimentally? Can you give me more insight on that? I have no physical model, everything is theorical.
 
r4m0n0 said:
Calculate U experimentally? Can you give me more insight on that? I have no physical model, everything is theorical.
Oh. You didn't say that. OK, how do you know the coolant flow rate to get the heat transfer coefficient on the tube side?

There are definitely heat transfer correlations available for air flow across banks of finned tubes. But you need to do the research yourself to find them.

Chet
 
Posted June 2024 - 15 years after starting this class. I have learned a whole lot. To get to the short course on making your stock car, late model, hobby stock E-mod handle, look at the index below. Read all posts on Roll Center, Jacking effect and Why does car drive straight to the wall when I gas it? Also read You really have two race cars. This will cover 90% of problems you have. Simply put, the car pushes going in and is loose coming out. You do not have enuff downforce on the right...
Thread 'Physics of Stretch: What pressure does a band apply on a cylinder?'
Scenario 1 (figure 1) A continuous loop of elastic material is stretched around two metal bars. The top bar is attached to a load cell that reads force. The lower bar can be moved downwards to stretch the elastic material. The lower bar is moved downwards until the two bars are 1190mm apart, stretching the elastic material. The bars are 5mm thick, so the total internal loop length is 1200mm (1190mm + 5mm + 5mm). At this level of stretch, the load cell reads 45N tensile force. Key numbers...
I'm trying to decide what size and type of galvanized steel I need for 2 cantilever extensions. The cantilever is 5 ft. The space between the two cantilever arms is a 17 ft Gap the center 7 ft of the 17 ft Gap we'll need to Bear approximately 17,000 lb spread evenly from the front of the cantilever to the back of the cantilever over 5 ft. I will put support beams across these cantilever arms to support the load evenly
Back
Top