Algebraic/Matrix Manipulation (linear algebra)

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Homework Help Overview

The discussion revolves around a problem related to algebraic and matrix manipulation within the context of linear algebra. The original poster seeks assistance with a question involving matrix equations and properties, specifically regarding conditions for non-trivial solutions.

Discussion Character

  • Exploratory, Conceptual clarification, Assumption checking

Approaches and Questions Raised

  • Participants explore the implications of the equation ##B^k Y = 0## and the properties of matrix B necessary for non-trivial solutions. Questions arise about the conditions under which a matrix multiplied by another results in zero, including considerations of determinants and invertibility.

Discussion Status

The discussion is active, with participants providing insights into the properties of matrices and the conditions for unique versus non-trivial solutions. Some guidance has been offered regarding the relationship between determinants and the existence of solutions, though multiple interpretations and understandings are still being explored.

Contextual Notes

There is a mention of the original poster's struggle with foundational concepts, indicating a possible gap in understanding that may affect their approach to the problem. The discussion reflects a learning environment where participants are revisiting basic properties of matrices.

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Homework Statement



I have attached the relevant question as an image (for sake of ease)

Homework Equations





The Attempt at a Solution



Also attached, in blue.


Thanks a lot for any help at all!
 

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You could consider ##B^k Y = 0##. Which property does B need to get non-trivial solutions for Y? How is that related to a?
##Y=(B-I_2)X##. How do you get Y=0 (which is a solution to the equation above) with non-trivial X? How is that related to a?
 
Perhaps the very beginning is where I'm having trouble, I don't know what times a matrix would be equal to zero. Is it the transpose? Or perhaps a matrix whose determinant is zero?
 
If you have studied matrices at all then you should know this basic property: the equation Ax= y has a unique solution if and only if A is invertible: x= A^{-1}y. And that is only true if A has non-zero determinant.

The equation Ax= 0 always has the "trivial" solution, x= 0. It has other solutions if and only if its determinant is 0.
 
You're right, I should know that basic property :) I've been cramming too much this semester so I tend to forget.

Thanks a lot it makes good sense.
 

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