1. The problem statement, all variables and given/known data The amplitude of vibration of a mass on a horizontal spring experiencing SHM is = 0.13m. The mass is 85g and the force constant is 55N/m. a) What is the maximum elastic potential energy of the system. b) Find the speed of the mass when it's position is x = 7.4cm from the equilibrium point. c) What is it's maximum speed? A = 0.13m m = 0.085Kg k = 55N/m Δx = 0.074m 2. Relevant equations Ee = ½k(Δx)2 Ek = ½mv2 Fx = -kΔx T = 2π√(m/k) Fc = mv2 / A 3. The attempt at a solution a) For this I simply used the Ee equation and solved for it. I used 0.13m as the amplitude as I figured this is the furthest the spring could stretch out. Ee = ½k(Δx)2 Ee = ½55N/m(0.13)2 Ee = 0.46J b) This one I solved for T, used the force equation and the Fc equation to solve for speed. T = 2π√(m/k) T = 2π√(0.086/55) T = 0.25s Fx = -kΔx Fx = -55(0.074) Fx = 4.07N Fc = mv2 / A Fc = (0.086)v2 / 0.13 v = 2.5m/s c) I am kind of lost and thought of making Ee = Ek but would like some assistance. Also if you could proof check my answers and tell me any errors as I assume my entire b) part maybe wrong.