An inclined plane, fixed to the inside of an elevator, makes a 32 degrees angle

AI Thread Summary
An inclined plane inside an elevator at a 32-degree angle is analyzed for a mass sliding down without friction while the elevator accelerates upward at 0.50g. The discussion focuses on the correct application of Newton's second law, particularly how to account for the normal force and the mass's weight in a non-inertial frame of reference. Participants clarify that the normal force should be broken down into components, and there is debate over whether to include the elevator's acceleration in the calculations. The consensus leans towards using kinematics to derive the mass's acceleration relative to the plane, while avoiding fictitious forces as per the teacher's instructions. The final calculations yield an acceleration of approximately 1.5g(tan32) for the mass relative to the inclined plane.
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Homework Statement



An inclined plane, fixed to the inside of an elevator, makes a 32 degrees angle with the floor. A mass m slides on the plane without friction. What is its acceleration relative to the plane if the elevator accelerates upward at 0.50g?

Homework Equations



F = ma

The Attempt at a Solution


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The free body diagram I have drawn involves FN and mg.
I made the relationship between these two like this:

FNcos32 - mg = 0.5mg (upward acceleration)
FNsin32 = m*ax

I've found that ax is 1.5g(tan32).
There is also the acceleration of elevator. But, because we are looking with respect to plane, we don't take it into consideration, do we?

I know that I can simply get the acceleration parallel to the plane just by adding the elevator's acceleration to gravity and multiplying it with sin32. Our teacher, however, doesn't want us to do these problems like that. So I am asking for help about my solution.
 
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First off, if 32 degrees is the angle between the plane and the floor, do you want F_n cos 32 for the vertical component? (as well as F_n sin 32 for the horizontal?) Second of all, if the mass is on a tilted plane, the weight force on the mass is not equal to mg.

Also, the normal force can essentially be broken down into 2 contributions, did you take both of these into account when you made your calculations?
 
BiGyElLoWhAt said:
First off, if 32 degrees is the angle between the plane and the floor, do you want F_n cos 32 for the vertical component? (as well as F_n sin 32 for the horizontal?) Second of all, if the mass is on a tilted plane, the weight force on the mass is not equal to mg.

Also, the normal force can essentially be broken down into 2 contributions, did you take both of these into account when you made your calculations?
Yes, FNcos32 is my vertical component, and since the mass is accelerating with elevator, I have written F= ma simply for the mass, that's why I chose to break FN rather than mg.
I'm sorry but can you be more clear on your second sentence?

F_Ncos32-mg=ma_elevator, F_Nsin32=ma_x.
This is all I've done. I believe this must satisfy Newton's second law.
From here you get a_x = 1.5gtan32
 
Ok so your y-axis lies along the plane? And your x-axis is into (normal to) the plane
The Normal force is generally mgcos theta. Thats for a plane that is static in the frame of reference. You could do that but it would be m"g"cos theta, which you said is not what your teacher wants you to do. I think you could probably get away with kinematics here, since there is no friction. Find the equation of motion for the plane, find the equation of motion for the block, and take the difference (you'll want to use something static like the elevator shaft as your reference). It's a pretty similar thing to summing the accelerations, though.

Also, you still have to break down mg. It seems as though you're being inconsistent with your coordinate systems. You're using one coordinate system for gravity, and another for the normal. You can't do that.
 
BiGyElLoWhAt said:
Ok so your y-axis lies along the plane? And your x-axis is into (normal to) the plane
The Normal force is generally mgcos theta. Thats for a plane that is static in the frame of reference. You could do that but it would be m"g"cos theta, which you said is not what your teacher wants you to do. I think you could probably get away with kinematics here, since there is no friction. Find the equation of motion for the plane, find the equation of motion for the block, and take the difference (you'll want to use something static like the elevator shaft as your reference). It's a pretty similar thing to summing the accelerations, though.

Also, you still have to break down mg. It seems as though you're being inconsistent with your coordinate systems. You're using one coordinate system for gravity, and another for the normal. You can't do that.

Let me make it clear that my teacher is not obsessed with not breaking down mg into components. He is just saying that "since it is no real force, you cannot draw ma_elevator next to mg in your free body diagram"

Here I drew my free body diagram.
http://www.sketchtoy.com/63667913
 
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you can't draw ma_elevator, but you can most definitely draw F_n next to your mg in your FBD. also, I can't view the picture. Can you just post it here in pf?
 
BiGyElLoWhAt said:
you can't draw ma_elevator, but you can most definitely draw F_n next to your mg in your FBD. also, I can't view the picture. Can you just post it here in pf?
I said that a_x = 1.5gtan32
If you break a_x into components in my diagram, you can see that it's "cos" component is equal to (1.5gsin32). This is also what you find exactly with your free body diagram: mgsin32+ma_elevatorsin32 = ma)
Z1bMna.png
 
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Oh man, I'm really sorry about that. The whole time I was saying F_n and thinking F_w.
I still think the kinematics is the way to go. If you sum the forces on the block, you can get the equation of motion for the block. You already know the equation of motion for the ramp.
 
BiGyElLoWhAt said:
Oh man, I'm really sorry about that. The whole time I was saying F_n and thinking F_w.
I still think the kinematics is the way to go. If you sum the forces on the block, you can get the equation of motion for the block. You already know the equation of motion for the ramp.
No problem with that. I'm going to give it a try with kinematics.
About finding the relative acceleration, we should neglect a_elevator since the plane and mass both have it, right?
 
  • #10
I probably wouldn't, but it should end up dropping out.
 
  • #11
This whole inertial and non inertial frame of reference thing messes this up.
In my calculations, I didn't have fictious forces involved, because I decided to choose an inertial frame of reference. But if I were to choose a non-inertial frame of reference, like the plane in elevator(the question was actually asking it as well), I could draw fictious forces, and that would be easier than what I've done, no doubt.
But since my teacher wants no fictious forces, I am obliged to to it in my way. So can I ask if my calculations, especially for a_x, are correct?
 
  • #12
I got a difference of approximately .16 m/s from your answer. I did not round, I used 9.8 for g.
 
  • #13
I applied superposition, eliminated gravity, and used that situation to model how the .5g acceleration affects the mass. Then I put a stationary ramp on the ground in Earth's gravitational field, and modeled how that affects the block. I then summed them together. Post your work and I'll look a little closer.
 
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