Analytical Mechanics: Proving Equilibrium at Bottom of Bowl

noor
Messages
4
Reaction score
0
Homework Statement
A point particle of mass m is confined to the frictionless surface of a spherical bowl. There are 2 degrees of freedom.
1. Prove that the equilibrium point is the bottom of the bowl. ,
2.Does the bowl need to be exactly spherical for this to be true ?
3. Near the bottom of the bowl what is the most general form possible for the shape of the bowl in order to maintain the stability of the equilibrium point at the bottom?
I found this problem in analytical mechanics book(Hand and Finch) and was trying to solve it.


Homework Equations





The Attempt at a Solution


In part one i used the p.e to find the eq point.
im not sure about part 2&3 please !
 
Physics news on Phys.org
For part 2 you could consider various surfaces of revolution like a cone or a parabolic shape and from there show whether a spherical surface is necessary.
 
Thread 'Need help understanding this figure on energy levels'
This figure is from "Introduction to Quantum Mechanics" by Griffiths (3rd edition). It is available to download. It is from page 142. I am hoping the usual people on this site will give me a hand understanding what is going on in the figure. After the equation (4.50) it says "It is customary to introduce the principal quantum number, ##n##, which simply orders the allowed energies, starting with 1 for the ground state. (see the figure)" I still don't understand the figure :( Here is...
Thread 'Understanding how to "tack on" the time wiggle factor'
The last problem I posted on QM made it into advanced homework help, that is why I am putting it here. I am sorry for any hassle imposed on the moderators by myself. Part (a) is quite easy. We get $$\sigma_1 = 2\lambda, \mathbf{v}_1 = \begin{pmatrix} 0 \\ 0 \\ 1 \end{pmatrix} \sigma_2 = \lambda, \mathbf{v}_2 = \begin{pmatrix} 1/\sqrt{2} \\ 1/\sqrt{2} \\ 0 \end{pmatrix} \sigma_3 = -\lambda, \mathbf{v}_3 = \begin{pmatrix} 1/\sqrt{2} \\ -1/\sqrt{2} \\ 0 \end{pmatrix} $$ There are two ways...
Back
Top