Angular momentum and change in velocity

In summary, the turntable has a moment of inertia of 2.5 x 10-2 kg m2 and is spinning at 33.3 rev/min. A 0.25 kg ball of putty is dropped 0.20 m from the center of the turntable. Using the equations L=Iω and L=r*p, the new angular speed of the system can be calculated by setting the initial angular momentum equal to the final angular momentum, giving the equation Iω = (I+mr)ω(final). After correcting for the units, the calculation results in a new angular speed of 24 rev/min, as confirmed by the answer key.
  • #1
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Homework Statement



A turntable has a moment of inertia of 2.5 x 10-2 kg m2 and spins freely at 33.3 rev/min. A 0.25 kg ball of putty is dropped vertically on the turntable at a point 0.20 m from the center. What is the new angular speed of the system?

a. 41 rev/min
b. 24 rev/min
c. 33 rev/min
d. 27 rev/min


Homework Equations



L=Iω
p=mv
L=r*p

The Attempt at a Solution



i tried to do Iω=(I+mr)ω(final)
i got 27 rev/min
the real answer is supposed to be 24rev/min according to the answer key
 
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  • #2
physgrl said:

Homework Statement



A turntable has a moment of inertia of 2.5 x 10-2 kg m2 and spins freely at 33.3 rev/min. A 0.25 kg ball of putty is dropped vertically on the turntable at a point 0.20 m from the center. What is the new angular speed of the system?

a. 41 rev/min
b. 24 rev/min
c. 33 rev/min
d. 27 rev/min


Homework Equations



L=Iω
p=mv
L=r*p

The Attempt at a Solution



i tried to do Iω=(I+mr)ω(final)
i got 27 rev/min
the real answer is supposed to be 24rev/min according to the answer key

Can you show the details of your calculation? We can't tell you what you did wrong if you don't show us your work!
 
  • #3
"i tried to do Iω=(I+mr)ω(final)"

Careful, mr does not have same units as I.
 
  • #4
Yeah that was my error thanks!
 

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