Angular momentum/angular velocity.

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A solid vertical cylinder with a mass of 10.0 kg and a radius of 1.00 m rotates at an angular speed of 7.00 rad/s when a 0.250 kg piece of putty is dropped onto it. To find the final angular speed after the putty sticks, the conservation of angular momentum principle is applied, stating that the initial angular momentum equals the final angular momentum. The moment of inertia of the cylinder is calculated using I = 1/2 MR^2, and the putty's contribution is added using the parallel axis theorem. The equation I_o * ω_o = I_f * ω_f is set up to solve for the final angular speed, ω_f. The discussion emphasizes the importance of correctly applying the moment of inertia and angular momentum concepts to solve the problem.
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Homework Statement



1.A solid, vertical cylinder of mass 10.0 kg and radius 1.00 m rotates with an angular speed of 7.00 rad/s about a fixed vertical axis through its center. A .250 kg piece of putty is dropped vertically onto the cylinder at a point 0.900 m from the center of ration and sticks to the cylinder. Determine the final angular speed of the system.


Homework Equations



Lbefore=Lafter
L=Iw

The Attempt at a Solution



the angular momentum is L and the angular velocity is what i am looking for that is w.
I believe you can say that IoWo should = IW

I am unsure what you are to do with the mass of the putty and the center of radian issue.

I believe you need to set up taht W = (Io/I)wo

Io = MR^2?
 
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I_{o}\times \omega_{o}=I_{f}\times \omega_{f}

We know I_{o}= \frac{1}{2}MR^2 plus we know wf

I_{f}=\frac{1}{2}MR^2+mr^2
Note: the I_{f} changes, the parallel axis theorm is used.

only \omega_f left that's unknown.
 
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