Angular Momentum of 2kg Particle Moving at 4.5m/s

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The discussion centers on calculating the angular momentum of a 2-kg particle moving at 4.5 m/s, with a focus on its distance from a point 6 m away from its straight-line path. There is confusion regarding the relationship between linear motion and angular momentum, with some participants mistakenly assuming circular motion is necessary for angular momentum calculations. The correct approach involves using the formula L = m * (r x v), where r is the perpendicular distance from the line of motion to the point of interest. Participants are encouraged to clarify their understanding of angular momentum in the context of linear motion. The conversation emphasizes the importance of grasping the definition and application of angular momentum beyond circular paths.
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a 2-kg particle moves at a constant speed of 4.5 m/s along a stright line. what is the magnitude of its angular momentum about a point 6 m from the line?

ok...so i really don't know what they mean by 'the particle is travling in a stright line about a point 6m away from the line'

doesn't angular momentum imply that the particle is travling in a circular path?

so i attemped this and L=Iw

w=rv and if the particle is travling about a point 6 m away, then the r should be 6

so L=Irv


but now for I...i don't know what to use becuase i am not sure how the particle is moving

but if it is moving in a cirlce as i think it should I=(2/3)mr^2

please help me to picture this problem
 
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You'll want to use the definition of angular momentum L=m*(rxv), where x is the cross product. Review this formulation for noncircular motion.
 

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