Angular velocity of an Electron

AI Thread Summary
In the Bohr Model of the Hydrogen Atom, the electron orbits a proton in a circular path with a radius of 5.3x10^-11 m. To find the constant speed of the electron, the relationship between angular velocity, radius, and velocity is utilized, alongside the net force equation F = ma. The radial acceleration can be derived from the velocity using the formula F = m(v^2/r). Additionally, Coulomb's law is applied to calculate the forces acting on the electron. The mass of the electron is 9.11x10^-31 kg, and the charge values for the electron and proton are also relevant for solving the problem.
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Homework Statement



In the Bohr Model of the Hydrogen Atom, a single Electron orbits a circle round a single stationary Proton. If the radius of the electron's orbit for its lowest energy state (the "ground state") is 5.3x10^-11m, find the the constant speed, v , of the orbiting electron .

Homework Equations



and calculate its kinetic energy in electron volts

The Attempt at a Solution



constant speed = angular velocity x radius (5.3x10^-11)
 
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The orbit also depends on the force on the particle
 
so how would i get the acceleration to use F = ma?
 
Well sort of. You know that the net force is F = ma, but you should also know how the force (or radial acceleration) on a particle in a circle path is related to its velocity. Also apply Coulomb's law and you should be able to solve for the velocity
 
F = m*(v^2/r)?
 
Do you have the mass of the electron, and the charge of the electron and proton?
 
9.11x10^031kg Mass of electron

1.6x10^-19 electron + proton?
 
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