Application of Heisenberg Uncertainty Principle

[Raghav Gupta]

I'm pretty convinced the answer $\ |p_y|\;d \ < \ h\$ is actually correct

Haha,
You were saying the other thing previously.

 

[BvU]

Are we back to posts 32, 35, 36 and have to go the loop again ?

 

[Raghav Gupta]

Are we back to posts 32, 35, 36 and have to go the loop again ?

Yeah, I think
There is confusion between two options
|p_y|d < h
|p_y |d ≅ h

 

[Raghav Gupta]

Are we back to posts 32, 35, 36 and have to go the loop again ?

Sorry for the post 53, it was non sensible.
Can you tell, if we have got from fowler Δp_yd ≈h
Then how | p_y| d < h ?
I have seen posts 32,35,36 carefully now.
You are saying this is not good exercise but anyways I am interested.

 

[Raghav Gupta]

(difference between $\Delta$ and | | isn't that big)

This statement was also a bit confusing from you for me
As I replaced Δp_yd ≈h
To |p_y|d ≈h
Because you are saying difference between these two signs are not big.

 

[BvU]

Sorry for the post 53, it was non sensible.
Can you tell, if we have got from fowler Δp_yd ≈h
Then how | p_y| d < h ?
I have seen posts 32,35,36 carefully now.
You are saying this is not good exercise but anyways I am interested.

The central maximum in the diffraction pattern from a single slit has a width Δp_y ≈ h / d (see Fowler). Most electrons end up in the central maximum, so for most electrons | p_y| d < h

I am having a bit of a deja vu feeling now.

 

[Raghav Gupta]

Okay, got it but not completely.
I have not read diffraction so much. I guess I have to know some very basic concepts first to understand whole of the fowler.
Will search myself for the moment.
Thanks by the way.

 

[BvU]

You're welcome. Don't forget #32: don't spend too much energy on this. It'll come by a few more times later on in the curriculum in different incarnations.