Approximating Glucose as an Ideal Gas: Can We Calculate Entropy?

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The discussion centers on the approximation of glucose dynamics in water as resembling an ideal gas, raising the question of whether entropy can be calculated using ideal gas equations. Participants express uncertainty about the specifics of calculating entropy and seek clarification on determining a lower bound for overall entropy change. One user indicates they have made progress on earlier tasks but are still confused about task four. The conversation highlights the need for further guidance on the calculations involved. Overall, the forum participants are collaboratively seeking solutions to the entropy calculation challenge.
Lambda96
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Homework Statement
Estimate the entropy of the glucose molecules (and only those) in
the initial state before the creation of the cell. Hint: You can approximate that their dynamics in water resembles that of an ideal gas.
Relevant Equations
No specific formulas were given
Bildschirmfoto 2022-11-11 um 14.07.42.png


For now it is only about the 1 task

If the task states that:

You can approximate that their dynamics in water resembles that of an ideal gas.
Does it then mean that I can take glucose as the ideal gas and then simply calculate the entropy for the ideal gas?
 
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Lambda96 said:
If the task states that:

You can approximate that their dynamics in water resembles that of an ideal gas.
Does it then mean that I can take glucose as the ideal gas and then simply calculate the entropy for the ideal gas?
Sorry you haven't had any replies. I am mostly unfamiliar with this topic, but the way the question is worded makes me think that you're on the right track. Best of luck.
 
Thanks Drakkith for getting in touch. I think task 1 to 3 I have now solved, I'm just a little unsure about the task 4, what exactly is meant by "Determine a lower bound for the overall entropy change"

Does anyone maybe have a tip for me, what I have to calculate exactly here?

Thanks
 
Thread 'Chain falling out of a horizontal tube onto a table'
My attempt: Initial total M.E = PE of hanging part + PE of part of chain in the tube. I've considered the table as to be at zero of PE. PE of hanging part = ##\frac{1}{2} \frac{m}{l}gh^{2}##. PE of part in the tube = ##\frac{m}{l}(l - h)gh##. Final ME = ##\frac{1}{2}\frac{m}{l}gh^{2}## + ##\frac{1}{2}\frac{m}{l}hv^{2}##. Since Initial ME = Final ME. Therefore, ##\frac{1}{2}\frac{m}{l}hv^{2}## = ##\frac{m}{l}(l-h)gh##. Solving this gives: ## v = \sqrt{2g(l-h)}##. But the answer in the book...

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