Assignment problem on Operational Amplifier

[lawteoh777]

The question is as given in the image attached entitled 'amplifier question' I would just like someone to check my working and verify whether it's correct or not. Thanks. And also want to ask on the second part which is 'what mathematical operation does this circuit perform?' Any help would be really appreciated.



Relevant equations would be V+ = V- I guess.



The attempt on my question is as attached in the image entitled 'amplifier question 2'

 

[berkeman]

The question is as given in the image attached entitled 'amplifier question' I would just like someone to check my working and verify whether it's correct or not. Thanks. And also want to ask on the second part which is 'what mathematical operation does this circuit perform?' Any help would be really appreciated.



Relevant equations would be V+ = V- I guess.



The attempt on my question is as attached in the image entitled 'amplifier question 2'

Your work looks correct to me. And for the second part of the question, what does the equation V = (V1 + V2)/2 look like to you? It should be the form of a familiar operation...

And the gain afterwards (from the output resistors) is just gain on top of the original operation.

 

[lawteoh777]

Really no idea on what the equation V = (V1 + V2)/2 looks like to me. It looks like average potential difference, but it doesn't make sense also. :/

 

[berkeman]

Really no idea on what the equation V = (V1 + V2)/2 looks like to me. It looks like average potential difference, but it doesn't make sense also. :/

That's what I would have called it, an average voltage. With gain afterwards. Not sure if it has a catchier name...

 

[DeeNos]

Thank you for providing your attempt at solving the amplifier question. After reviewing your work, I can confirm that your calculations and approach are correct. Your use of the equation V+ = V- is also correct, as the operational amplifier is an ideal device that has a virtual short between its two input terminals. This means that the voltage at the inverting input (V-) is equal to the voltage at the non-inverting input (V+).

As for the mathematical operation performed by this circuit, it can be described as a non-inverting amplifier with a gain of 10. This means that the output voltage is 10 times the input voltage. This can be expressed as Vout = 10Vin, where Vin is the input voltage and Vout is the output voltage.

I hope this helps to verify your work and answers your question about the mathematical operation performed by the circuit. Keep up the good work!