Calculating Force from Atmospheric Pressure on Sheila's Palm

AI Thread Summary
To calculate the force exerted on Sheila's palm by atmospheric pressure, the correct formula is F = P * A, where F is force, P is pressure, and A is area. Given that the area of Sheila's palm is 0.0017 m² and the atmospheric pressure is 100,000 Pa, the force can be calculated as F = 100,000 Pa * 0.0017 m². This results in a force of approximately 58823.53 N. The discussion clarifies the formula manipulation needed to derive the force from pressure and area. The final answer confirms the calculation of force based on the provided values.
Gamer_Hedwig
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ok my problem is that the question asks
The palm of Sheila's hand has an area of 0.0017m2.If the atmospheric pressure on the palm is 100,000 Pa, what force is being exerted on Sheila's palm by the atmosphere?

I know the formula is not P=F/A
I know you have to change the formula around but I don't know which way...
is it F=P/A?Or something esle?

Thanks for people that are answering!
 
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Um...can't remember this formula off the top of my head, but if you start with P=F/A, you can't get it to F=P/A.
 
Pressure is F/A. Manipulating it gets you F=PA
 
P = F / A leads to

F = P*A
 
thanks...
i got the answers as 58823529.41
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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