Back E.M.F. & Torque Output of a Permanent Magnet DC Motor

AI Thread Summary
Back electromotive force (back e.m.f.) in a permanent magnet DC motor acts as a counter voltage generated by the armature's rotation, proportional to its speed. Initially, when back e.m.f. is zero, the voltage across the armature is at its maximum, resulting in maximum current and torque. As the motor speeds up, back e.m.f. increases, reducing the voltage and current, which leads to a decrease in torque. At maximum speed, back e.m.f. equals the applied voltage, resulting in no current and thus no torque. Understanding this relationship is crucial for grasping motor performance under varying loads.
OutCell
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Hi,

What is the effect of "back e.m.f." on the torque output of a permanent magnet d.c. motor? I googled it but didn't get any results.. I just need a brief description to understand the concept..

Thanks :blushing:
 
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when armature of dc motor rotates, it also acts as a generator also n generates a counter emf(lenz law) which is called back emf. now this back emf is proportional to the speed at which the armature is rotating. at a particular speed it becomes equal to the applied voltage. this is the maximum speed of the dc motor.
at the start, when back emf is zero, voltage across armature(applied voltage-back emf) is maximum, current is maximum, therefore torque is maximum(torque is proportional to current in the armature, T = I*L*B*r, I current, L length of conductor,B magnetic field, r = radius, school physics). as the speed builds up, back emf increases, voltage across armature drops, current drops and therefore torque starts to decrease.
finally when speed is maximum, ie applied voltage= back emf, no current, no torque. therefore at no load n maximum speed, motor has no torque
 
ank_gl said:
when armature of dc motor rotates, it also acts as a generator also n generates a counter emf(lenz law) which is called back emf. now this back emf is proportional to the speed at which the armature is rotating. at a particular speed it becomes equal to the applied voltage. this is the maximum speed of the dc motor.
at the start, when back emf is zero, voltage across armature(applied voltage-back emf) is maximum, current is maximum, therefore torque is maximum(torque is proportional to current in the armature, T = I*L*B*r, I current, L length of conductor,B magnetic field, r = radius, school physics). as the speed builds up, back emf increases, voltage across armature drops, current drops and therefore torque starts to decrease.
finally when speed is maximum, ie applied voltage= back emf, no current, no torque. therefore at no load n maximum speed, motor has no torque

Thanks mate! :rolleyes:
 
no probs dude. pleasure to help u
 
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