Ball rolling off an inclined plane

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SUMMARY

The discussion centers on calculating the distance a ball travels off an inclined plane over time, specifically after 3 seconds given it travels 10 cm in the first second. The relevant equations include v = l/t, v = v0t + at, and x = x0 + v0t + at²/2. The correct calculation shows that the ball will travel 0.9 meters in 3 seconds, correcting an initial miscalculation that suggested 0.45 meters. The key takeaway is the importance of using the correct kinematic equations for non-constant acceleration scenarios.

PREREQUISITES
  • Understanding of basic kinematics, including acceleration and distance calculations.
  • Familiarity with the equations of motion: v = l/t, v = v0t + at, and x = x0 + v0t + at²/2.
  • Knowledge of inclined plane physics and how gravity affects motion.
  • Ability to manipulate algebraic equations to solve for unknowns.
NEXT STEPS
  • Study the principles of kinematics in detail, focusing on non-constant acceleration scenarios.
  • Learn about inclined plane dynamics and the effects of angle on acceleration.
  • Explore practical applications of the equations of motion in real-world physics problems.
  • Practice solving similar problems involving rolling objects and varying acceleration.
USEFUL FOR

Students studying physics, particularly those focusing on mechanics and kinematics, as well as educators looking for examples of inclined plane problems and their solutions.

Avathacis
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Homework Statement



A ball is rolling off an inclined plane. After 1 second the ball has traveled 10cm. How far will it travel in 3 seconds?

Homework Equations



v = l/t
v = v0t + at
x = x0 + v0t + at2/2

The Attempt at a Solution



v = l/t1

v = v0t + at (there's no starting velocity, so)

l/t1 = at1

l = at21

a = l/t21

l3 = x0 + v0t + at2/2

l3 = at2/2

l3 = (l/t21 + t2) 1/2

l3 = 0.45m

The answer should be 0.9m, so i guess I'm supposed to lose the 1/2 somewhere.
 
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Avathacis said:
v = l/t
This only applies if the speed is constant, which is not the case here.

x = x0 + v0t + at2/2
Use this to figure out the acceleration.
 
Doc Al said:
This only applies if the speed is constant, which is not the case here.


Use this to figure out the acceleration.

Thanks! Done!
 

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