Basic KCL Problem: Solve Node Equations

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The discussion focuses on solving node equations using Kirchhoff's Current Law (KCL) for a circuit problem. At node a, the equation is established as 6 = io + Is, while at node b, Is is expressed as Is = io/4 + I8. It is noted that nodes a and b can be treated as the same due to equal voltage. Participants emphasize the importance of Ohm's Law (V=IR) for calculating currents I8 and Io. The conversation concludes with a suggestion to use these relationships to solve for Io and Vo effectively.
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Homework Statement



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Homework Equations



KCL

The Attempt at a Solution



abl2z6.png


At node a: 6= io + Is
At node b: Is= io/4 + I8

Couldn't go much further.
 
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two things to note:

1.)a and b can be considered the same node as their voltage is the same.

2.)Also for calculating values such as I8 and Io, remember ohms law. V=IR
try to use that relationship to finish your equation.
 
Vo=I8*8, Vo=Io*2 --> Vo=Vo, I8*8=Io*2 --> I8=Io/4?
 
JasonHathaway said:
Vo=I8*8, Vo=Io*2 --> Vo=Vo, I8*8=Io*2 --> I8=Io/4?

So now you can solve for Io and Vo...
 
Thank you very much :)
 
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