Q_Goest
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If you extract energy of random motion from the molecules and turn this into a systematic energy of flow, then in a reference frame moving with the flow, the shape of the velocity distribution function must obviously change because of energy conservation.
Sorry, but I disagree with the assumption we've extracted any type of energy from the flow. First, conservation of energy still applies regardless of how that energy manifests itself. Second, we're not talking about a real flow, just a close approximation. Bernoulli's assumes only a conservation of mechanical energy, and disregards thermal. That's a close approximation so long as velocity is not too high and the overall length of the streamline is short.
In this case, the kinetic energy of any given molecule remains the same. It is simply being directed or steered in a given direction. A car traveling on a frictionless set of railroad tracks that makes a turn does not have any change in it's kinetic energy. Similarly, there is no change in the kinetic energy of the individual molecules as they are steered in a given direction. The overall kinetic energy of the flow is changed, but only at the expense of loosing it in another direction. Note that Bernoulli's is "frictionless" such that no mechanical energy is lost, and this is not a real case. In reality, some energy is converted.
But this would correspond to a decrease in temperature as the flow speeds up, which I don't think will be observed here …
You're correct in saying the temperature will NOT decrease, but that's because the kinetic energy of the molecules is assumed to stay constant.
Imagine gas in a box with molecules in random motion. The pressure is the same in all directions. But given an infinite amount of time, there can be a state where all the molecules just happen to be moving in the same direction at the same time. Needless to say, that's highly unlikely, but it's not statistically impossible. When that happens, we find the dynamic pressure in the direction of motion is higher while the pressure perpendicular to the motion decreases. A venturi simply creates that affect for molecules flowing through it.
Also, what Andrew said:
Absent friction, the flow of a contained fluid is conservative of energy so it is analagous to a reversible thermodynamic process.
… is correct, except it's not analagous to a reversible process. It IS a reversible process. There is no dQ/dT so entropy change = 0 The entire process is isothermal as you've mentioned before and I agree. But that's only because of the assumptions made, not because it really is purely isothermal. Real fluid flows experience real pressure drops, but given the assumptions made for Bernoulli's the result is a constant entropy process. The entropy throughout the flow is isentropic. If you Google 'Bernoulli's isentropic' you'll find the isentropic assumption is valid.
http://www.google.com/search?hl=en&q=bernoulli+isentropic
I just wanted to also mention that you raise a lot of very incitefull questions, and I think we all learn more from that type of questioning than we can learn without it. So I sincerely would like to thank you for flushing out all these considerations, I certainly feel I've had to learn things better in order to provide a valid argument.