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Block and Pulley question

  1. Nov 3, 2009 #1
    1. The problem statement, all variables and given/known data
    The 100 kg block in figure takes 5.60 s to reach the floor after being released from rest.
    What is the mass of the other block. The distance between the 100 kg block and the floor is 1m.


    2. Relevant equations
    f=ma
    Xf=Xi+Vi(Tf-Ti)+(.5)(a)(Tf-Ti)^2


    3. The attempt at a solution
    ????
     
  2. jcsd
  3. Nov 3, 2009 #2

    rl.bhat

    User Avatar
    Homework Helper

    Both blocks must move with the same acceleration. Tension in the string is the same. Apply the Newton's second law for both the masses.
    Like for the known mass
    100*g - T = 100*a.
    Similarly write down the equation for the unknown mass. Solve for T.
    Distance moved by the block is given and time is given. Using the relevant equation find the acceleration. Using T and a, find the unknown mass.
     
  4. Nov 3, 2009 #3
    k thx that did the trick
     
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