Block attached to spring - calculate how far it will move

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A spring with a constant of 200 N/m holds a block weighing 20 N, and the problem involves calculating how far the block will move before stopping. The initial attempts using force equations yielded incorrect results, prompting a shift to energy conservation principles. The correct approach equates gravitational potential energy to elastic potential energy, leading to the formula mgh = 0.5kx^2. By substituting values, the correct distance the block moves before stopping is determined to be 0.2 m. Understanding the energy conservation method is crucial for validating the solution.
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Homework Statement


A spring with spring constant 200 N/m is suspended vertically with its upper end fixed to the ceiling and its lower end at position y = 0. A block of weight 20 N is attached to the lower end, held still for a moment, and then released. How far will the block move before coming momentarily to a stop?

Homework Equations


mg = -kx
mg = 0.5kx^2

The Attempt at a Solution


I tried using the first equation and got x = 0.1m as my ans. which was wrong. I then tried using the second equation instead and still got an incorrect answer. Where am I going wrong? The ans. is 0.2 m.

Thanks in advance!
 
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You need to look at this problem from an energy conservation standpoint.
 
The block comes to a stop when its speed is zero. Your approach is invalid because the speed of the block is not necessarily zero when the net force acting on the block is zero.
 
Hmm ok would it be something like this? mgh = 0.5kx^2 and the x and the h are the same? Cuz then solving for h I get (2mg)/k and when I subbed in the number I got 0.2. Is this the right way of doing this problem?
 
Looks like a good way to get the answer!
 
Your answer is correct; however, it is important you understand why the approach is valid. Do you?
 
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