Bulk modulus and poisson's ratio

AI Thread Summary
The discussion focuses on deriving the equation for bulk modulus, K = E/3(1 - 2v), where v is Poisson's ratio. The user attempts to relate strain and stress components, expressing total strain as e_v = e_x + e_y + e_z, and identifies that e_y and e_z are influenced by Poisson's ratio. A hint is provided to consider the equations for the individual strain components and the effect of uniform hydrostatic pressure on stress components. The conversation clarifies that the factor of 3 arises from the total hydrostatic pressure being the sum of equal stress components, emphasizing the negative sign due to compression. Understanding these relationships is crucial for correctly deriving the bulk modulus equation.
ABoul
Messages
26
Reaction score
0

Homework Statement


derive the equation for the bulk modulus, K = E/3(1 - 2v), where v is poisson's ratio.


Homework Equations


E = stress/e, where e is strain


The Attempt at a Solution


e_v = e_x + e_y + e_z
e_y = e_z = -v*e_x
e_v = (1 - 2v)*e_x

K = stress/e_v
therefore K = stress/[(1 - 2v)*e_x]

i am out by a factor of 1/3. where have i gone wrong?
 
Physics news on Phys.org
Here is a hint. e = epsilon sub x + epsilon sub y + epsilon sub z. Look at the equations for epsilon sub x, epsilon sub y, and epsilon sub z.

For instance, epsilon sub x = (sigma sub x) / E - (v*sigma sub y) / E - (v*sigma sub z) / E.
 
Perhaps this will bring the answer out.

A body subjected to a uniform hydrostatic pressure all three stress components are equal to a -p.
 
CFDFEAGURU said:
Perhaps this will bring the answer out.

A body subjected to a uniform hydrostatic pressure all three stress components are equal to a -p.

i see. so the total hydrostatic pressure is the sum of all components, and that's where the factor of 3 comes in, right?
 
Yes that is right. But it is a negative 3. You are in compression.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top