Cahnge in potential difference of moving electron

[Kastner86]

Homework Statement

As an electron moves through a region of space, its speed increases from 2.2e^6 m/s to 6.0e^6 m/s. The electric force is the only force acting on the electron.

a) Did the electron move to a higher potential or a lower potential?

b)Across what potential difference did the electron travel?

Homework Equations

well for part b, I'm not even sure what to use.

K = 1/2mv^2

U=q x V

The Attempt at a Solution

Well i know part a), the electron moves to a higher potential.

I really don't know how to solve this since the distance or time is not given. And I may be confused as to the difference between potential difference and electric potential. I don't know where to start!

 

[rl.bhat]

a) Electron moves in the apposite direction to the electric field. In the electric field the potential decreases along its direction. Then...?
b) The electron accelerates when it moves through lower potential to the higher potential. Hence its kinetic energy increases. Use the relevant equations and find the potential difference.

 

[Kastner86]

Yes, i understand the electron is accelerating. obviously, its speed increases, so its kinetic energy also increases. I understand all these concepts.

I don't know which equations to use. That is where I'm stuck. All the equations I can think of using velocity have time or distance variable, which i can't use.

The only one I know is K = 1/2mv^2

So would I do \DeltaK = 1/2mv₂^2 - 1/2mv₁^2

and since \DeltaK = - \DeltaU_E

I can then use \DeltaV = \DeltaU/e to get the potential difference?

Is \DeltaV potential difference or just potential or electric potential?? that is one area I am confused.

Thank you

 

[rl.bhat]

Yes. ΔV = ΔU/e. No area is involved.

 

[Kastner86]

This worked!

A big thanks to you. Sometimes just trying to explain the problem to someone else helps me solve it anyways.

Thanks!