Cal 2 ratio test where is my mistake

Jac8897
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cal 2 ratio test "where is my mistake"

Homework Statement


I attached a pic
I solved the problem but i get 4^1 and the book says 4^2 I don't know why?

Homework Equations



http://img690.imageshack.us/img690/1518/problem15.jpg

The Attempt at a Solution

 
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when you sub in for n -> n+1 in exponent of the 4 it should be

\frac{4^{(2n+1)}}{4^{(2(n+1)+1)}}
 


lanedance said:
when you sub in for n -> n+1 in exponent of the 4 it should be

\frac{4^{(2n+1)}}{4^{(2(n+1)+1)}}

got it

thank you
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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