- #1
mateomy
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I don't remember ANYTHING from this section when I took Trig but we're finding the area of curves in the polar coords. Looking at the book they give us this equation
[tex]
r=2cos3\theta
[/tex]
I can see, and I know how to figure out its a 3 leaf "rose" symmetrical about the theta= zero axis, but I can't figure out the next part which is the author stating "Finding the intervals we see that [itex]\theta[/itex]=pi/6, 3pi/6, 5pi/6, 7pi/6, 9pi/6, and 11pi/6." Maybe (probably) its simple trig stuff that I am overlooking but how the H do they find those values?
Pointers, suggestions, and/or degrading comments will be greatly appreciated. Thanks.
[tex]
r=2cos3\theta
[/tex]
I can see, and I know how to figure out its a 3 leaf "rose" symmetrical about the theta= zero axis, but I can't figure out the next part which is the author stating "Finding the intervals we see that [itex]\theta[/itex]=pi/6, 3pi/6, 5pi/6, 7pi/6, 9pi/6, and 11pi/6." Maybe (probably) its simple trig stuff that I am overlooking but how the H do they find those values?
Pointers, suggestions, and/or degrading comments will be greatly appreciated. Thanks.
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