Calculate Electric Field Between -30 & +50 uC Charges

AI Thread Summary
The discussion focuses on calculating the electric field between two point charges, -30 µC and +50 µC, separated by 17.0 cm. The initial calculations for the electric fields produced by each charge were attempted using the formula E=kq/r², but there was confusion regarding the net electric field direction at the midpoint. It was clarified that the net electric field at that point should be the sum of the two fields, as they act in the same direction. The correct direction of the electric field halfway between the charges is towards the negative charge, as it attracts positive test charges. The participants confirmed the calculations and clarified the concept of electric field direction.
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Homework Statement



Two point charges, -30 and +50 , are separated by a distance of 17.0 cm . (micro couloumbs)

Express your answer to two significant figures and include the appropriate units.

Homework Equations



E=kq/r^2

The Attempt at a Solution


E1=9E9*30E-6/.085^2= 3.73*10^7
same for E2 =6.23*10^7
E2-E1=2.5E7 N/C
Really not sure on how to do this, i was just doing what seemed logical to me but the procedure could be entirely wrong. ( I am sure that my answer is wrong)
 
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If you are finding the net field at the center of the line joining the charges, then the electric fields at the center are in the same direction. So the net field at that point is E = E1 + E2.
 
thanks, i now have the correct answer but part to of the question is What is the direction of the electric field at a point halfway between the two charges?

I think that it would be toward the positive charge since it is bigger?
 
E is defined as the force acting on unit positive charge.
 
so it would actually be toward the negative charge since the positive charge would repel it?
 
Correct
 
thanks dadface
 
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