Calculate EMF: 3.25 ohm, 440 mH, 3.00 A, 3.60 A/s

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To calculate the electromotive force (emf) across a coil with a resistance of 3.25 ohms and an inductance of 440 mH, the formula emf = -L dI/dt is used. Given that the current is increasing at a rate of 3.60 A/s, the emf can be calculated by substituting the values into the equation. The resulting emf indicates the potential decrease across the coil at that moment. The discussion also reflects on the importance of accurately applying the formula despite personal challenges. Accurate calculations are essential for understanding the behavior of electrical components in circuits.
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A coil has a 3.25 ohm resistance and 440 mH inductance. If the current is 3.00 A and is increasing at a rate of 3.60 A/s, what is the potential decrease across the coil at this moment?

The only equation I know to use is

emf = - L dI/dt
 
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Hi Shackleford,

Shackleford said:
A coil has a 3.25 ohm resistance and 440 mH inductance. If the current is 3.00 A and is increasing at a rate of 3.60 A/s, what is the potential decrease across the coil at this moment?

The only equation I know to use is

emf = - L dI/dt

What would be the emf across a 3.25 ohm resistor in this situation?
 
alphysicist said:
Hi Shackleford,



What would be the emf across a 3.25 ohm resistor in this situation?

Hello. Sorry. I took another quick stab at this problem and solved it correctly. I've kind of had a cold/mild flu lately.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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