Calculate Frictional Force & Acceleration of 3.5kg Box on Floor

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To calculate the frictional force and acceleration of a 3.5 kg box pushed by a 15N force at a 40-degree angle, first, a free body diagram is essential to visualize the forces acting on the box. The applied force has both horizontal and vertical components, which must be calculated to determine the net force. The normal force is affected by the vertical component of the applied force and the weight of the box, which in turn influences the frictional force calculated using the coefficient of kinetic friction (0.25). The net force is then used to find the acceleration of the box by applying Newton's second law. Properly summing these forces will lead to the desired calculations.
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A 3.5 kg box is pushed along a horizontal floor by a force F of magnitude 15N at an angle of 40degrees below the horizontal. The coefficient of kinetic friction is 0.25. Calculate the magnitude of the frictional force on the block from the floor and the acceleration of the block.

I don't really know where to start.

Can anyone Help?
 
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The sum of all the forces acting on the block equals the mass of the block times acceleration. You just need to account for all the forces properly.
 
Start exacty where you start with all problems of this nature. With a free body diagram. Draw your forces and the components. Sum the componts and procede.

Show us your work.
 
Thread 'Variable mass system : water sprayed into a moving container'

Thread 'Variable mass system : water sprayed into a moving container'

Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
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