Calculate Linear Velocity: 180 deg/s & 0.5 m

AI Thread Summary
To calculate the linear velocity of the foot given an angular velocity of 180 degrees/s and a distance of 0.5 m from the knee joint, the formula used is linear velocity = angular velocity (w) x radius (r). Converting 180 degrees to radians gives approximately 3.14 rad/s, leading to a linear velocity of about 1.57 m/s when multiplied by the radius. There were some concerns about unit handling, particularly regarding the use of degrees in the calculation. It is noted that radians can be considered dimensionless in this context, simplifying the calculation. The final answer, rounded to two decimal places, is 1.57 m/s.
PepperABLF12
Messages
6
Reaction score
0

Homework Statement



What is the linear velocity of the foot if the angular velocity of the dynamometer was 180 degrees/s and the distance from the knee joint to the foot is 0.5 m. Give your answer rounded to two decimal places in m.s-1. (Do not include units in answer).

Homework Equations



linear velocity = angular velocity (w) x radius (r).
linear velocity = w x r.

The Attempt at a Solution



w = 180 degree/s
r = 0.5m
linear velocity = ?

linear velocity = w x r
linear velocity = 180 x 0.5
linear velocity = 90 degrees/s

To find radians, 90/57.3 = 1.57 m/s

Is this correct? And in the right units?

Please help and thank you! :)
 
Physics news on Phys.org
Well, your relevant equation gives ##0.5 {\rm m}\, \times \,\pi \, {\rm rad/s} = 1.57 \,{\rm m/s}## straightforward.

But your dealing with units is a bit messy. Especially the 90 degrees/s is objectionable. A linear velocity has dimension length/time. The numerics are fine, but the dimensions should read something like: degrees/s / radians/degree x meters/radian

THe writer of the exercise doesn't want to be bothered by these considerations, so he/she asks for a number only.

In my first sentence I let the radians disappear, you could say that I cheat too. My defence is: radians is arc per radius, so length/length and thereby dimensionless: it can be skipped in dimensional expressions.
 
  • Like
Likes 1 person
Thank you so much! Great help :)
 
It is easier to understand if you convert to radians first and then calculate the linear velocity.
 
  • Like
Likes 1 person
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top