Calculate New Load - rig application

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A rig accelerates a load of 200,000 lbf vertically from zero to 60 ft/min in 5 seconds, requiring the calculation of the new load on the hook load indicator. The distance of the load during acceleration is calculated to be 4.99 ft. The tension in the cable is influenced by both the weight of the load and the additional force needed for acceleration. Participants in the discussion emphasize the importance of deriving the total force equation for the accelerating load. The conversation highlights the need for clarity in calculations and understanding the forces at play in rig operations.
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Homework Statement


A rig accelerates a load of 200,000 lbf from zero to 60 ft/min in 5 seconds.

Homework Equations


Compute new load shown on the hook load indicator ?

The Attempt at a Solution


Calculated the distance of load l = 4.99 ft.
 
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Zak Brigadier said:

Homework Statement


A rig accelerates a load of 200,000 lbf from zero to 60 ft/min in 5 seconds.

Homework Equations


Compute new load shown on the hook load indicator ?

The Attempt at a Solution


Calculated the distance of load l = 4.99 ft.
Can you please show more of your work? Can you attach a diagram of the problem? Is all of this acceleration vertical?
 
Hello Berkeman:

Thank you for your reply. I don't have a diagram attached. Yes the acceleration is vertical. The hook lowers/hoist loads vertically in a drilling rig.
 
So the two things creating the tension in the cable is the weight of the load, and the extra force needed to generate that acceleration. Can you start to write down the equation for the total force on the accelerating object now? :smile:
 
Yes.

P-T = ma
 
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