Calculate Speed of Water Ejected from Hose

  • Thread starter Thread starter dvyu
  • Start date Start date
  • Tags Tags
    Forces Speed
AI Thread Summary
To calculate the speed of water ejected from a hose, one must consider the flow rate and the cross-sectional area of the hose. The initial attempt at calculation yielded a speed of 2.09E-3 m/s, which was incorrect due to misinterpretation of flow units. The correct formula relates area, flow, and velocity, with flow expressed in liters per second. After addressing unit conversions and applying the correct formula, the expected speed aligns with the textbook's answer of 21.2 cm/s. Clarification on the relationship between area, flow, and velocity was essential for resolving the confusion.
dvyu
Messages
34
Reaction score
0
It takes 30.0s to fill a 2.00-L container with water from a hose with a constant radius 1.00cm. The hose is held horizontally. Determine the speed of the water being ejected from the hose.

I have attempted this question, but I have got a different answer to my textbook. I may however be going about this the wrong way.

Attempt:
4p(0.01)/30^2 = 2pV/30
V = 2.09E-3 m/s
 
Physics news on Phys.org
What exactly does your attempt represent?

How is the flow defined and how can you calculate it from the given data? Further on, how does the flow relate to the area and speed?
 
oh yes - I was using acceleration formulae
So, I should be using
area = flow/velocity and flow = Litre/second
 
dvyu said:
oh yes - I was using acceleration formulae
So, I should be using
area = flow/velocity and flow = Litre/second

Try to do so.
 
I have used that formula -
velocity = (2/30)/(3.14*0.01^2) = 212.2m/s
The thing is, my textbook gives the answer as 21.2cm/s, and my answer converts to 2.12cm/s. Am I wrong or is the textbook wrong?
 
Your answer is wrong.
 
Okay - can you tell me where I went wrong, because I can't see where I went wrong
 
dvyu said:
Okay - can you tell me where I went wrong, because I can't see where I went wrong

You went wrong with the flow units. 1 [L] = 1 [dm^3]. Convert to [cm^3].
 
okay, thanks, I'll try again

~it's worked out, thanks for your help
 
Last edited:
  • #10
Sorry, a better question is why is area equal to flow / velocity and since 1 L equals 1dm wouldn't 1L equal to 10cm? So than why do we have r as 0.1?
velocity = (2/30)/(3.14*0.01^2) = 212.2m/s

Oh i see you are converting 1cm into dm. I still can't grasp how area = flow / velocity?
 
Last edited:
Back
Top