Calculate the heat capacity of this calorimeter

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To calculate the heat capacity of the calorimeter, the heat lost by the hot water must equal the heat gained by the calorimeter and the cooler water. The formula Q = mcΔT can be applied, where Q is the heat exchanged, m is the mass of the water, c is the specific heat capacity, and ΔT is the change in temperature. For the hot water, the heat lost can be calculated using its mass, specific heat capacity, and the temperature difference from 65 C to the final temperature. The calorimeter's heat capacity can be determined by rearranging the equation to solve for it, considering the total heat gained by the calorimeter and the cooler water. The discussion also raises the question of whether this calorimeter is better or worse than the one used in sample calculations, which would depend on its heat capacity value compared to the standard. Understanding the definition of heat capacity is crucial for solving this problem effectively.
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When using a different calorimeter, and mixing 50 ml of hot water at 65 C with 60 ml of water in the calorimeter at 25 C, the temperture of the calorimeter increased by 5.5 C. Calculate the heat capacity of this calorimeter. Is this a better or worse calorimeter than the one used in the sample calculations?

This problem gets me all confused? Is there a formula that would make it easier? please help
 
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As with all problems, if they ask for X. The first thing you want to ask yourself is, what is the definition of X? In this case heat capacity.
 

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