Calculate the Lagrangian of a coupled pendulum system

Click For Summary
To calculate the Lagrangian of a coupled pendulum system with two ropes of different lengths attached to a plank, first express the kinetic and potential energies in terms of generalized coordinates. The kinetic energy includes contributions from the center of mass motion and rotational motion of the plank. The massless strings constrain the rod's movement, which can be represented through the angles and positions of the rod's ends. By determining these relationships, the velocities and angular velocities can be derived. This approach will ultimately lead to finding the normal frequencies and modes of the system.
DeldotB
Messages
117
Reaction score
8

Homework Statement



Calculate the Lagrangian of this set up:

Imagine having two ropes: They are both attached to the ceiling and have different lengths. One has length b and the other has length 4b. Say they are hooked to the ceiling a distance 4b apart. Now, the ropes are both hooked to a plank of mass M (uniform mass density) of length 5b. The rod can move in 3 dimensions. Ultimately, I am after the normal frequencies and normal modes of the system, but I think I can determine these if I can figure out this lagrangian

x3ilqr.png

Homework Equations



\mathcal{L} = T-U

The Attempt at a Solution



Well, I am not entirely sure how to go about this but my book suggests to use the coordinate x for the longitudinal displacement of the rod and y_1 and y_2 as the sideways displacement of the rods two ends. Also, we are only assuming small displacements from equilibrium (so I think \dot{z} is going to be zero)
Im not sure how to implement this choice of generalized coordinates.

Can anyone help me out? Also, I have never found a lagrangian for an extended object (its always been point masses in various systems)

Thanks in advance - btw I cannot find ANYTHING online that resembles a problem like this.
 
Physics news on Phys.org
I suggest you go about it in the usual way. Write down the lagrangian of the system by expressing the kinetic and potential energies, then express those in terms of the generalised coordinate(s).
 
I've never written down the lagrangian of an extended object. I realize the K.E of the plank would be the K.E of its center of mass (\frac{1}{2}m( \dot{x}^2+ \dot{y}^2) ) and probably some rotational K.E like \frac{1}{2} I \omega^2 but I don't know how the strings affect these terms...
 
DeldotB said:
I've never written down the lagrangian of an extended object. I realize the K.E of the plank would be the K.E of its center of mass (\frac{1}{2}m( \dot{x}^2+ \dot{y}^2) ) and probably some rotational K.E like \frac{1}{2} I \omega^2 but I don't know how the strings affect these terms...
The strings are massless. All you have to figure out is how they constrain the movement of the rod. You can do this by expressing the rod position (angle and com) in terms of your generalised coordinate and taking the time derivative to find the velocity and angular velocity of the rod.
 

Similar threads

  • · Replies 15 ·
Replies
15
Views
3K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 2 ·
Replies
2
Views
5K
Replies
9
Views
4K
Replies
3
Views
2K
  • · Replies 11 ·
Replies
11
Views
2K
Replies
6
Views
3K
  • · Replies 4 ·
Replies
4
Views
4K
Replies
5
Views
2K
Replies
2
Views
2K