Calculate the velocity on which the pump will fill

  • Thread starter Thread starter mzhades
  • Start date Start date
  • Tags Tags
    Pump Velocity
AI Thread Summary
To calculate the velocity at which the pump fills the water box, the power of the pump (1 kW) is used to determine the work done over time. The work is calculated using the formula for gravitational potential energy, which incorporates mass, gravity, and height (5m). The energy supplied by the pump is partially converted into potential energy to elevate the water. The remaining energy contributes to the kinetic energy of the water, allowing for the calculation of velocity. Understanding these relationships is crucial for determining the pump's efficiency and performance.
mzhades
Messages
1
Reaction score
0

Homework Statement



A water pump of 1 kilowatt of potency supplies a water-box located 5m above of the water-box where the pump is located. Calculate the velocity on which the pump will fill the water-box.

NOTE: Sorry for the bad English.

Homework Equations



potency = work/time

work= mass x gravity x height
 
Physics news on Phys.org
The rate at which the pump is doing work - 1 kW - tells us the amount of energy that is supplied to the water per second. Part of this energy is used to raise the water's potential energy. The rest of the energy will then become the ...
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top