Calculate the z component of the torque relative to position

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magma_saber
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Homework Statement


http://img3.imageshack.us/img3/5681/32832.jpg

All seven forces have a magnitude |F| = 32 N. w = 10 m, h = 16 m, and d = 15 m. Calculate the z component of the torque relative to position A.

Homework Equations


T = r*F


The Attempt at a Solution


Not sure how to start this.
F1 = F*h*w = 32*16*10?
F2 = F*h = 32*16?
 
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T = r X F

So you want to figure the force acting at a perpendicular to the point at interest.

In this case your r X F1 will equal |F1|*h, where h is the distance at which it is acting ⊥ to a line through A.
 


LowlyPion said:
T = r X F

So you want to figure the force acting at a perpendicular to the point at interest.

In this case your r X F1 will equal |F1|*h, where h is the distance at which it is acting ⊥ to a line through A.

i tried that, its wrong. it says the z component. would that make a difference?
 


magma_saber said:
i tried that, its wrong. it says the z component. would that make a difference?

The resultant of r X F is a z component by the right hand rule for taking a cross product.

Of course you still need to sum up all the other torques from the other forces.
 


it asks just for the torque for each force that is applied, i.e. F1, F2, F3, ect. After that, it asks for the net torque. for F1 i tried F*h and it was wrong. Would it be F*h*w, since the tail starts at w?
 


magma_saber said:
it asks just for the torque for each force that is applied, i.e. F1, F2, F3, ect. After that, it asks for the net torque. for F1 i tried F*h and it was wrong. Would it be F*h*w, since the tail starts at w?

Sorry I thought you were supposed to be determining the sum.

The |T| is F1*h. But because it is the cross product of y X x, that yields a clockwise torque that is -z

So for F1 you have the z component is -|F1*h|z

Counterclockwise torques are positive. Clockwise are negative.
http://en.wikipedia.org/wiki/Right-hand_rule