Calculating Acceleration from High Speed Camera Footage

AI Thread Summary
To calculate the average acceleration of a 50g ball rebounding off a wall, the initial velocity is 25 m/s and the final velocity is -22 m/s, resulting in a change in velocity of -47 m/s. The contact time with the wall is 3.5 ms, or 0.0035 seconds. Using the formula for acceleration, the average acceleration is calculated as -47 m/s divided by 0.0035 s, yielding approximately 13.4 x 10^3 m/s². The confusion arose from the calculation of the change in velocity, which was clarified during the discussion. The final answer confirms the expected result of 1.34 x 10^4 m/s².
gr3g1
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I have a question in my serway physics book..
The question goes like this:

A 50g ball traveling at 25m/s bounces off a brick wall and rebounds at 22m/s. A high speed camera records this event. If the ball is in contact with the wall for 3.5ms what is te magnintue of te average acceleration of te ball durning this time interval..

I tried using delta v over delta t to find the answer, but the answer is suppose to be : 1.34*10^4

Thanks
 
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gr3g1 said:
I tried using delta v over delta t to find the answer, but the answer is suppose to be : 1.34*10^4
Thanks

The approach is correct and the answer it gives is indeed 13.4*10^3 m/s^2
 
Ok , the orignal v is 25, and the final v is 22.
The time is just .0035

-3/.0035 ?
 
Where did the "3" come from?
 
the change is 3 m/s
 
Wait, Nevermind, I got it
 
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