Calculating Angular Velocity at the End of a Time Interval

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SUMMARY

The discussion centers on calculating the angular velocity of a wheel with a constant angular acceleration of 2.0 rad/s² over a 2.0-second interval, during which it completes 2.165 revolutions. The kinematic equation used is θf = θi + ωi*t + 0.5*α*t². Participants express confusion regarding their calculations, as their results exceed the provided answer options of 9.7 rad/s, 9.1 rad/s, 9.3 rad/s, 9.5 rad/s, and 8.8 rad/s, indicating a potential misunderstanding of the equation or its application.

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Homework Statement


A wheel rotating about a fixed axis with a constant angular acceleration of 2.0 rad/s2 turns through 2.165 revolutions during a 2.0 s time interval. What is the angular velocity at the end of this time interval?


Homework Equations


I was using the kinematic Equations
\thetaf = \thetai + \omegait + 0.5\alphat2

Am i doing something wrong?
The answers that I can choose are, 9.7 rad/s, 9.1 rad/s, 9.3 rad/s, 9.5 rad/s, 8.8 rad/s

All the answers I get are way larger

I must be doing something obviously wrong but I just can't see it.
 
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Lets see your work then.
 

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