Calculating Constant Force for a 150-kg Merry Go Round with a 1.50m Radius

  • Thread starter Thread starter sbpatel
  • Start date Start date
  • Tags Tags
    Homework
AI Thread Summary
To calculate the constant force required to accelerate a 150-kg merry-go-round with a radius of 1.50m to an angular speed of 0.500 rev/s in 2.00 seconds, first determine the moment of inertia for a disk, which is I = 0.5 * m * r^2. Next, calculate the necessary angular acceleration using the formula α = (ω_final - ω_initial) / time, converting angular speed from revolutions per second to radians per second. Apply Newton's second law for rotation, τ = I * α, to find the torque, and then relate torque to force using τ = r * F. Finally, solve for the constant force F needed to achieve the desired acceleration.
sbpatel
Messages
5
Reaction score
0
A 150-kg merry go round in the shape of a horizontal disk with a radius of 1.50m is set in motion by wrapping a rope about the rim of the disk and pulling on the rope. What constant force would have to be exerted on the rope to bring the merry-go-round from rest to an angular speed of .500 rev/s in 2.00s.
 
Physics news on Phys.org
hint:
what is the inertia of a disk?
what angular acceleration is required to bring the m-g-r to that speed in that given time?
Use Newton's second law relating Torque to inertia and angular acceleration.
Use rotational kinematics equations to solve for angular acceleration and speed ( don't forget to convert the rev/s to radians/s before using these equations... you'll have to convert back to rev/s once you get the answer)

Show any work you've gotten so far and we'll add assistance.
 
Last edited:
well i really have no clue how to do this problem. My physics teacher genius is a but he does not know how to teach. Could someone please show me how to do it?
 
MathStudent just told you exactly what you have to do. It's up to you to do it. Give it a try and see how it goes. If you still can't figure it out, then come back and show us what you did.
 
TL;DR Summary: I came across this question from a Sri Lankan A-level textbook. Question - An ice cube with a length of 10 cm is immersed in water at 0 °C. An observer observes the ice cube from the water, and it seems to be 7.75 cm long. If the refractive index of water is 4/3, find the height of the ice cube immersed in the water. I could not understand how the apparent height of the ice cube in the water depends on the height of the ice cube immersed in the water. Does anyone have an...
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top