Calculating Electric Field at 0.8m from Charges on x-Axis

AI Thread Summary
To calculate the net electric field at 0.8m on the x-axis from two charges, one at the origin (-15*10^-6 C) and another at 0.55m (3.5*10^-6 C), the principle of superposition should be applied. First, determine the electric field contributions from each charge using the formula E = k*q/r^2, where k is Coulomb's constant. The distances from the point of interest (0.8m) to each charge must be calculated to find the individual fields. After calculating the individual electric fields, sum them to find the net electric field at the specified point. This approach effectively combines the effects of both charges to determine the resultant electric field.
soul5
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Homework Statement


A charge of 3.5*10^-6 is fixed on the x-axis at x= 0.55m, while a charge of -15*10^-6 is fixed at the origin. What is the net electric field on the x-axis at 0.8m?


Homework Equations


Fe = qE



The Attempt at a Solution


Used Fe = qE, but that's it.
 
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Hi soul5!

How about using q/r^2? :smile:
 
Apply the principal of super position. The field at any point is the sum of the two individual fields at that same point when acting independently...IE work out the individual fields at x=0.55m and then add them together.
 
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