Calculating Electric Field Strength and Acceleration in a Coulombic System

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To calculate the electric field strength at the location of a 40 microcoulomb test charge in an electric field created by a 5 coulomb charge, the force experienced (6 Newtons) can be used with the formula E = F/q, resulting in an electric field strength of 150,000 N/C. The acceleration of the test charge can be determined using Newton's Second Law (F = ma), leading to an acceleration of 2 x 10^14 m/s² when the mass of the test charge is 3 x 10^-20 kg. The discussion emphasizes the relationship between force, charge, and electric field, clarifying that 5 coulombs refers to charge, not force. Additionally, the distance between the charges can be calculated using the formula for electric force, which incorporates Coulomb's constant. Understanding these principles is essential for solving problems in a Coulombic system.
llama0lover
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A 40 Micro Coluomb test charge is placed in an electric field produced by a 5 Coloumb charge. It expierences a 6 Newton force. What is the strength of the electric field at this point? If the test charge has a mass of 3 x 10 ^ -20 Kg, what acceleration does it expierence?


I Think I could use the 6 Newton force and divide it by the first force 5 Coloumbs to get the electric field, and then on from their I could use a force table get the acceleration, but I am not exactly positive how to set up the Free body diagram and force table for this.

I'm Just stuck on how to find the acceleration really
 
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llama0lover said:
I Think I could use the 6 Newton force and divide it by the first force 5 Coloumbs to get the electric field, ...

1. How is force on a charge related to the electric field in which this charge finds itself?
2. 5 coulombs is a charge not a force
3. Assuming that you know the force on the charge and the mass of the charge. What does Newton's Second Law say about the acceleration?
 
oh you can use F=ma to figure out the acceleration thanks :-) also, how would you know where the first charge the 5 coluombs was in relation the the test charge?
 
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You can find the distance (if you really wanted to) with the definition of electric force, F - (kq1q2)/d2. You know F and the charges, and k's a constant. And distance can't be negative, so you don't have to worry about that when evaluating the square root ;)

(hello classmate! See, I TOLD you I'd get on here!)
 
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