Calculating Equilibrium Mass in a Pulley System

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Homework Help Overview

The problem involves calculating the mass required for equilibrium in a pulley system, specifically related to a truck on a slope. The context suggests considerations of torque and mechanical advantage, with assumptions about negligible mass and friction in the pulleys.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • The original poster attempts to set the sum of net torques to zero for equilibrium but questions their calculation after arriving at an unexpected mass. Participants inquire about the number of cables supporting the truck's weight and discuss the implications of mechanical advantage.

Discussion Status

Participants are actively engaging with the problem, exploring different interpretations of the setup. Some guidance is offered regarding the number of cables, which leads to a revised calculation by the original poster. There is acknowledgment of the reasoning process but no explicit consensus on the final answer.

Contextual Notes

There is a lack of explicit information regarding the number of cables in the original problem statement, which has led to some confusion among participants. The original poster's calculations and assumptions are being scrutinized in light of this ambiguity.

twerkit
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Homework Statement



Find the mass necessary for equilibrium to occur in the following image. Assume that the mass and the friction of the pulleys are negligible.

giiiiirl-1.png


Homework Equations



None directly provided for this problem.

The Attempt at a Solution



I figured for this problem I would set the sum of the net torques on the pulley equal to zero, because then the pulley is not spinning and the system is in equilibrium.

Here is my equation:

gravity = 9.8 m/s

Since torque is the cross product of the force times the perpendicular distance from the axis of rotation, I used counterclockwise torque (provided by the truck) = F*rsin(x), but since the force is already perpendicular to the axis of rotation in the image I just used F*r, where the F = 1500*9.8*sin(45). The clockwise torque on the pulley is m*g*3r

ƩT = 1500kg*9.8*sin(45)*r - m*g*3r = 0

add m*g*3r to both sides and then divide by r to obtain:

ƩT = 1500kg*9.8*sin(45) = m*g*3

solving for the mass I get 353 kg, but the answer is 178 kg.

I noticed that multipying the right side by 6 instead of 3 yields the right answer, I just don't know why or what I'm doing wrong.
 
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How many cables support the truck's weight?
 
gneill said:
How many cables support the truck's weight?

I don't know, the question is literally this :

"Find the mass necessary for the truck to be balanced on the slope in the figure. Assume that the mass and frictions of the pulleys are negligible."

That is all it says, no information regarding how many cables or the like is given.
 
twerkit said:
I don't know, the question is literally this :

"Find the mass necessary for the truck to be balanced on the slope in the figure. Assume that the mass and frictions of the pulleys are negligible."

That is all it says, no information regarding how many cables or the like is given.

Doesn't the picture make it clear? How many cables with tension T are holding the truck?

(Think: mechanical advantage)
 
gneill said:
Doesn't the picture make it clear? How many cables with tension T are holding the truck?

(Think: mechanical advantage)

Ah, I thought you were asking me as if you needed more information! So since two cables are supporting the truck, I divide my answer by two and get approximately 178 kg.
 
That looks about right. Well done.
 
gneill said:
That looks about right. Well done.

Thank you for the eye opener :-)
 

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