Calculating Friction & Coefficient: 0.50 kg Block on 30° Ramp

AI Thread Summary
To determine the force of friction opposing a 0.50 kg block sliding down a 30° ramp with an acceleration of 2.0 m/s², the net force is calculated using the equation F = ma. The gravitational force acting on the block is broken into components, with the parallel component being 0.5mg * sin(30°) and the normal force as mg * cos(30°). The required frictional force is found by rearranging the equation to F = 0.5mg - ma. The coefficient of friction is then calculated using the relationship F(friction) = F(normal) * coefficient of friction. This analysis leads to the conclusion that both the force of friction and the coefficient of friction can be determined through these calculations.
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Homework Statement



A block of mass 0.50 kg slides down a 30 degree ramp.

a) What force of friction opposes the motion of the block in order to make the acceleration equal to 2.0 m/s/s?

b) What coefficient of friction is necessary in order to accomplish this?

Homework Equations



f=ma

The Attempt at a Solution



net force=(9.8*.5)*sin30

2.45=.5(a)
a=4.9 m/s/s?
 
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Horizontal component of weight is mgsin(30) = 0.5mg
normal component = mgcos(30) = sqrt(3) * mg/2

0.5mg - F = ma

So F = 0.5mg - ma, we found F

Also F = mu * sqrt(3) * mg/2

mu = F/(sqrt(3) * mg/2)
 
Use F=ma to find the force needed. a is 2 and m is 0.5. Then break the black's force of gravity into components qith trig. Subtract the force from F=ma from the force going down the ramp to get frictional force. The difference between the forces must be from friction. Simply find the normal force and use F(friction)= F(normal)(coefficient of friction)
 
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