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a wreacking ball is used to demolish a building. The 600-kg ball starts from rest, with it's 37-m-long cable making a 22 degrees angle with the vertical. it strikes the building when the cable is vertical. What is the speed of the ball on impact?
it doesn't seem like a hard question, but i can't figure it out.
U_o =mgL(1-cos(\theta))
K_0 = 0
U_f = 0
K_f = 1/2mv^2
mgL(1-cos(\theta)) = 1/2mv^2
V= \sqrt{\frac{gL(1-cos(\theta))}{2}}
plugging in known values, i get 3.6 but the book gets 7.3 m/s. am i missing something?
it doesn't seem like a hard question, but i can't figure it out.
U_o =mgL(1-cos(\theta))
K_0 = 0
U_f = 0
K_f = 1/2mv^2
mgL(1-cos(\theta)) = 1/2mv^2
V= \sqrt{\frac{gL(1-cos(\theta))}{2}}
plugging in known values, i get 3.6 but the book gets 7.3 m/s. am i missing something?