Calculating Jet Plane's Acceleration After Full Throttle

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To calculate the jet plane's acceleration after full throttle, the initial velocity (Vi) is 300 m/s, and the final velocity (Vf) is 400 m/s over a displacement of 2 km (2000 m). The appropriate kinematic equation to use is Vf² = Vi² + 2a*s. Substituting the known values into the equation allows for solving the acceleration (a). The correct calculation yields an acceleration of 10 m/s². This method effectively determines the jet's acceleration during the specified interval.
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Homework Statement



A jet plane is cruising at 300 m/s when suddenly the pilot turns the engines up to full throttle. After traveling 2 km, the jet is moving with a speed of 400 m/s. What is the jet's acceleration (in m/s/s) during this interval assuming the acceleration to be constant?


Homework Equations



I was thinking that in order to go further you would have to solve for the seconds? So I used v=m/s and solved for s, which was then 5s. But I'm not sure where to go from there?

Help?
 
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Initial and final velocities are given. Displacement is given. Find the kinematic equation which relates Vi, Vf, x and a. And solve for a.
 
But the only kinematic formulas I find include time, which isn't given.
 
Well, I tried vf=vi+a(t) but I got 20m/s/s, which was wrong.
 
Allura said:
Well, I tried vf=vi+a(t) but I got 20m/s/s, which was wrong.

v2f - v2i = 2as

Substitute the values and find a. Here s = 2000 m.
 

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