Calculating Magnetic Field Needed for Proton Beam

AI Thread Summary
To keep a proton beam moving horizontally in a uniform magnetic field while counteracting gravity, the magnetic force must equal the gravitational force acting on the protons. The relevant equation is B = qv/F, where B is the magnetic field strength, q is the charge of the proton, v is its velocity, and F is the gravitational force. The discussion emphasizes the need to equate the gravitational force (Fg) with the magnetic force (Fb) to find the required magnetic field strength. Participants note that additional information may be necessary to complete the calculations. The solution involves substituting known values into the equations to derive the magnetic field strength needed.
kristibella
Messages
18
Reaction score
0

Homework Statement


A beam of protons is accelerated to a speed of 5.0x10^6 m/s in a particle accelerator into a uniform magnetic field. What B field perpendicular to the velocity of the proton would cancel the force of gravity and keep the beam moving exactly horizontally?

Homework Equations


B = qv/F


The Attempt at a Solution


I haven't made any attempts because I don't think that I was given enough information...
 
Physics news on Phys.org
Begin with Fg = Fb (force of gravity equals magnetic force).
Fill in the detailed formulas, then solve for what you are looking for.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top