The problem involves calculating the maximum possible resolution of an electron microscope, given that electrons are accelerated by 2450 V. The discussion centers around the application of de Broglie's wavelength equation and the relationship between momentum and energy in the context of electron microscopy.
The discussion is active, with participants sharing their attempts at calculations and seeking clarification on concepts. Some guidance has been provided regarding the relationship between energy, momentum, and the equations needed to approach the problem, though confusion remains about specific steps and interpretations.
Participants express uncertainty about the definitions and relationships between voltage, energy, and momentum, indicating a need for further exploration of these concepts. The original poster is new to the forum and is navigating the expectations of the homework context.
rude man said:Hint #1: deBroglie
Hint #2: Rayleigh
No. Why would you multiply m and e? It doesn't make any sense.Airplane7 said:So by using deBroglie equation lambda=h/p.. i'd have to do
6.63x10^-34Js / ((9.11x10^-31)(1.60x10^-19)) ??
vela said:No. Why would you multiply m and e? It doesn't make any sense.
Redbelly98 said:Moderator's note: I have moved this thread to Introductory Physics. In the future, please post questions of this level in Introductory Physics.
The information given for V can be used to find p.
No. The v in p=mv represents the velocity of the particle. The V in 2450 V stands for volt; it's a unit of electric potential. They're not the same thing at all.Airplane7 said:Lol, I'm not sure.. I'm confused on solving the question..
So, to find p, it's p=mv right? so (9.11 x 10^-31kg)(2450 v) ?
That's the basic idea, but you need to find the electron's momentum first.When i find the solution of p, plug it into lambda=h/p, so (6.63x10^-34 Js) / p , will give me the maximum resolution?