Calculating Momentum of a Falling Mass: 30.00 kg Object from 4.00m Height

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Homework Help Overview

The problem involves calculating the momentum of a 30.00 kg mass that falls from a height of 4.00 m. The focus is on determining the momentum just before impact, which requires finding the velocity of the mass at that point.

Discussion Character

  • Exploratory, Mathematical reasoning

Approaches and Questions Raised

  • Participants discuss methods to find the velocity needed for the momentum calculation, including the use of kinematic equations and energy conservation principles.

Discussion Status

Some participants have suggested different approaches to find the velocity, including using kinematic equations and energy conservation. There appears to be a productive exchange of ideas, with at least one participant expressing satisfaction with the guidance received.

Contextual Notes

There is a mention of kinematic equations and energy conservation principles, indicating that participants are considering multiple methods to approach the problem. The original poster expresses difficulty in determining the velocity needed for the momentum calculation.

ckaiser813
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Homework Statement


A 30.00 kg mass falls from a height of 4.00m. The momentum of the mass just before it hits the ground is?


Homework Equations



obviously p=mv

The Attempt at a Solution



I just can't figure out how to get a velocity for this formula?
 
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ckaiser813 said:

Homework Statement


A 30.00 kg mass falls from a height of 4.00m. The momentum of the mass just before it hits the ground is?

Homework Equations



obviously p=mv

The Attempt at a Solution



I just can't figure out how to get a velocity for this formula?

Consider one of these kinematic equations:
https://www.physicsforums.com/showpost.php?p=905663&postcount=2
 
There are 2 ways to do this.

1) Find the velocity using kinematic equations:
x = \frac{1}{2}gt^2
you know x and g so you can solve for t. After solving for t you can get the velocity from v=gt.

2) You can also use energy conservation
KE=\frac{1}{2}mv^2=PE=mgh
and then applying the knowledge of what KE is and momentum is
KE=\frac{p^2}{2m}
to find p directly.
 
yes sir that helped me figure out what the book got, thanks a bunch!
 

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