Calculating Output of Op-Amp in Given Circuit

AI Thread Summary
The discussion revolves around calculating the output of an op-amp in a given circuit, specifically an inverting amplifier configuration. Participants apply Kirchhoff's Current Law (KCL) to derive the output voltage, initially calculating it as 20V before realizing the need for a negative sign due to the inverting nature of the circuit. The correct output is confirmed to be 0V after incorporating the negative sign in the calculation. The importance of recognizing the input type and its impact on the output is emphasized. Overall, the conversation highlights the critical role of understanding circuit configurations in op-amp calculations.
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Homework Statement


Calculate the output of the op-amp as shown in the given circuit.
http://img9.imageshack.us/img9/7554/184v.png
(Answer=0)

Homework Equations


Kirchhoff's Current Rule


The Attempt at a Solution



By applying KCL,
I1+I2=I3
V1/R1 + V2/R2 = Vo/R3
Substituing the values and rearranging the equation we get,
Vo= (5/10,000 + 2/4,000)*20,000
Vo= 20
But then I realized that if i use a minus sign between (5/10,000 + 2/4,000), I get Vo=0...
So does that minus sign come into the equation because we're trying to find out the output of an inverting amplifier, or is it simply because V2="-"2
 
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This type of circuit is known as adder or summer

AdderAmp.gif


The solution is given by:

vo = - RF * [ V1/R1 + V2/R2 + ... + Rn/Rn]

SOLUTION:

Vo = - 20k * [ 5/10k + -2/4k] ; I think you forgot to use negative signs
Vo = 0
 
Mr.Green said:
Vo = - 20k * [ 5/10k + -2/4k] ; I think you forgot to use negative signs
Vo = 0

Why did you put a minus sign before 20k?
 
Since the input is on the inverting input a negative sign should be used.
On yourpost you didn't specify the type of inputs of the op-amp, but it seems that the input is on the inverting input.
 
Yeah you're right...thanks
 
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