Calculating Potential Difference in an Electric Field with Given Field Equation

[chopnhack]

Homework Statement

An electric field is given by Ex = 2.2x + 5x²kNC^-1. Find the potential difference between two points on the x-axis at x = -2.0 m and x = 2.0 m

Homework Equations

∫5x²+2.2x from -2 to 2

The Attempt at a Solution

I got the answer of 27V.

Solution said - negative 27V

Can someone please explain?
Thanks

 

[NFuller]

∫5x2+2.2x from -2 to 2

Remember there is a negative sign in front of this integral since
$$\mathbf{E}=-\nabla V$$.

 

[kuruman]

$\Delta V = -\int_{-2}^2{\vec{E} \cdot d\vec{s}}$
You left out the negative sign.

 

[chopnhack]

Remember there is a negative sign in front of this integral since
$$\mathbf{E}=-\nabla V$$.

yes, sadly I recall it now...

 

[chopnhack]

I was so happy to have found the proper way of handling it, I didn't recall the formula!
Thanks all.