Calculating Resistance of Aluminum Cylinder

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To calculate the resistance of an aluminum cylinder, the mass and density of aluminum can be used to determine the volume, which in turn allows for the calculation of the cylinder's dimensions. Given that the diameter equals the height, the area of the circular face can be calculated using the formula A = π(d/2)². The length of the cylinder is equal to its height, which is the same as the diameter. The resistance can then be calculated using the formula R = ρL/A, where ρ is the resistivity, L is the height (or diameter), and A is the area. Understanding these relationships is crucial for accurately determining the resistance of the aluminum cylinder.
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Not an actual problem, but I'm not sure how to figure these out.

I am given the mass of a sample of aluminum. (Let's say it's 112g or something) I am given a shape: cylindrical tube, with the conditions that the diameter of the circular face = the height. (Also given, density of aluminum, a chart with the resistivity values, at standard temp of 20C). How on Earth would I find the resistance between the top and the bottom face of the shape?
 
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R = pl/A (Resistance = resistivity * length/area) is probably the equation to use. But I have no length? The mass given, and density can find the length somehow? (I would use area of a circle only correct?)
 
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Is the shape a "cylindrical tube" or just a cylinder?

Since you haven't given a tube wall thickness I'm assuming you mean a cylinder.

But I have no length?
But you said,
diameter of the circular face = the height
 
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